Question

question 4 of 10
a parking lot is going to be 40 m wide and 100 m long. which dimensions could be used for a scale model of the lot?
a. 75 in × 225 cm
b. 100 cm × 300 m
c. 10 cm × 25 cm
d. 25 cm × 75 cm

Explanation:

Step1: Find the ratio of original dimensions

The ratio of the length to the width of the parking - lot is $\frac{100}{40}=\frac{5}{2}$.

Step2: Check the ratios of each option

Option A:

First, convert 75 in to cm. Since 1 in = 2.54 cm, 75 in = 75×2.54 = 190.5 cm. The ratio of the dimensions is $\frac{225}{190.5}
eq\frac{5}{2}$.

Option B:

The units are inconsistent (100 cm and 300 m). Also, if we consider the ratio ignoring units for a moment, $\frac{300\times100}{100}=300
eq\frac{5}{2}$.

Option C:

The ratio of the dimensions is $\frac{25}{10}=\frac{5}{2}$, which is the same as the ratio of the original parking - lot dimensions.

Option D:

The ratio of the dimensions is $\frac{75}{25}=3
eq\frac{5}{2}$.

Answer:

C. 10 cm × 25 cm