Question

question 3
10 pts
a classroom measures 10 meters × 15 meters × 4 meters. the suspended particulates in this room were determined to be 55 microgram per cubic meter. what is the total mass (in grams) of suspended particulates in the room?

Explanation:

Step1: Calculate room volume

$V = 10\times15\times4=600$ (cubic - meters)

Step2: Calculate total mass in micrograms

$m_{\mu g}=55\times V = 55\times600 = 33000$ (micrograms)

Step3: Convert micrograms to grams

Since $1$ gram = $10^{6}$ micrograms, $m_{g}=\frac{33000}{10^{6}}=0.033$ (grams)

Answer:

$0.033$