Question

question 5 of 10
solve the following system of equatic
pair in the format (a,b), with no space
3x + 4y = 17
-4x - 3y = -18

Explanation:

Step1: Eliminate a variable (e.g., x)

Multiply the first equation by 4: \(4(3x + 4y) = 4\times17\) → \(12x + 16y = 68\)
Multiply the second equation by 3: \(3(-4x - 3y) = 3\times(-18)\) → \(-12x - 9y = -54\)

Step2: Add the two new equations

\((12x + 16y) + (-12x - 9y) = 68 + (-54)\)
Simplify: \(7y = 14\)

Step3: Solve for y

Divide both sides by 7: \(y = \frac{14}{7} = 2\)

Step4: Substitute y = 2 into the first original equation

\(3x + 4(2) = 17\) → \(3x + 8 = 17\)

Step5: Solve for x

Subtract 8: \(3x = 17 - 8 = 9\)
Divide by 3: \(x = \frac{9}{3} = 3\)

Answer:

(3,2)