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question 2 of 10 step 1 of 1 00:59:08 solve the quadratic equation by the square root method and write the solutions in radical form. simplify the solutions. \\(2y^2 = 96\\) answer 2 points \\(y = \\) or keyboard shortcuts keypad
Step1: Isolate $y^2$ term
Divide both sides by 2:
$\frac{2y^2}{2} = \frac{96}{2}$
$y^2 = 48$
Step2: Take square roots of both sides
Apply square root property:
$y = \pm\sqrt{48}$
Step3: Simplify the radical
Factor 48 into perfect square:
$\sqrt{48} = \sqrt{16\times3} = \sqrt{16}\times\sqrt{3} = 4\sqrt{3}$
So $y = \pm4\sqrt{3}$
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$y = 4\sqrt{3}$ or $y = -4\sqrt{3}$