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Question
question 5 of 10 step 1 of 1 simplify the following expression. ( i^{108} )
Step1: Recall $i$ cycle property
$i^1=i,\ i^2=-1,\ i^3=-i,\ i^4=1$; cycle length=4
Step2: Divide exponent by 4
$\frac{108}{4}=27$, remainder=0
Step3: Match remainder to cycle
Remainder 0 corresponds to $i^4$
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