Question

question 3 of 10, step 1 of 1 solve the following quadratic equation by factoring. if needed, write your answer as a fraction reduced to lowest terms. \\( y^2 - 10y + 16 = 0 \\) \\( y = \\) or

Explanation:

Step1: Factor the quadratic trinomial

We need two numbers that multiply to $16$ and add to $-10$. These numbers are $-2$ and $-8$.
$y^2 - 10y + 16 = (y - 2)(y - 8) = 0$

Step2: Apply zero product property

Set each factor equal to 0.
$y - 2 = 0$ or $y - 8 = 0$

Step3: Solve for $y$

Solve each linear equation.
$y = 2$ or $y = 8$

Answer:

$y = 2$ or $y = 8$