Question

question 6 of 10
a television of mass 12 kg sits on a table. the coefficient of static friction between the table and the television is 0.83. what is the minimum applied force that will cause the television to slide?
a. 118 n
b. 98 n
c. 83 n
d. 75 n

Explanation:

Step1: Calculate the normal force

The normal force $N$ on a horizontal surface for an object of mass $m$ is equal to its weight $mg$. Given $m = 12\ kg$ and $g= 9.8\ m/s^{2}$, so $N=mg = 12\times9.8=117.6\ N$.

Step2: Calculate the maximum static - friction force

The formula for the maximum static - friction force $F_f=\mu_sN$, where $\mu_s = 0.83$ and $N = 117.6\ N$. So $F_f=0.83\times117.6\approx97.6\ N\approx98\ N$. The minimum applied force to make the television slide is equal to the maximum static - friction force.

Answer:

B. 98 N