Question

question 11 (1 point)which of the following statements concerning motion graphs is not correct?○ the slope of a position-time graph gives velocity.○ the area under a velocity-time graph gives displacement.○ the slope of a velocity-time graph gives acceleration.○ the area under an acceleration-time graph gives velocity.○ the slope of the tangent in a position-time graph gives instantaneous velocity.question 12 (1 point) ✓ savedthe cosine and sine law method for calculating the sum of displacement vectors can only be used for two vectors at a time.○ true○ false

Explanation:

For Question 11:

• Slope of position-time graph is velocity ($v=\frac{\Delta x}{\Delta t}$), so first statement is correct.
• Area under velocity-time graph is displacement ($\Delta x=\int v dt$), so second statement is correct.
• Slope of velocity-time graph is acceleration ($a=\frac{\Delta v}{\Delta t}$), so third statement is correct.
• Area under acceleration-time graph is change in velocity ($\Delta v=\int a dt$), not velocity, so this statement is incorrect.

For Question 12:
The sine and cosine laws (triangle method) can be used to add two or more vectors by combining two at a time iteratively, so the claim that they only work for two vectors is false.

Answer:

Question 11: C. The area under an acceleration-time graph gives velocity.
Question 12: False