Question

question 17 of 25
two shoes each have a mass of 0.1 kg. if they are 0.15 m apart, what is the gravitational force between them? g = 6.67×10^(-11) n·(m/kg)^2

a. 4.44×10^(-11) n
b. 2.96×10^(-11) n
c. 4.44×10^(-12) n
d. 2.96×10^(-10) n

Explanation:

Step1: Identify the formula

The formula for gravitational force is $F = G\frac{m_1m_2}{r^2}$, where $G$ is the gravitational - constant, $m_1$ and $m_2$ are the masses of the two objects, and $r$ is the distance between them.

Step2: Substitute the given values

Here, $m_1 = m_2=0.1\ kg$, $r = 0.15\ m$, and $G = 6.67\times10^{-11}\ N\cdot(m/kg)^2$.
$F=(6.67\times 10^{-11})\frac{0.1\times0.1}{(0.15)^2}$

Step3: Calculate the value

First, calculate $0.1\times0.1 = 0.01$ and $(0.15)^2=0.0225$.
Then, $\frac{0.01}{0.0225}=\frac{100}{225}=\frac{4}{9}\approx0.444$.
$F=(6.67\times 10^{-11})\times0.444\approx 2.96\times 10^{-11}\ N$

Answer:

B. $2.96\times 10^{-11}\ N$