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question 23
as we mentioned in chapter 1, in the u.s. system, a temperature is measured on the fahrenheit scale. in the metric system, temperature is measured on the celsius scale. on the celsius scale, water boils at 100 degrees and freezes at 0 degrees. to denote a temperature of 100 degrees on the celsius scale, we write 100°c, which is read \100 degrees celsius\
table 1 is intended to give you an intuitive idea of the relationship between the two temperature scales. table 2 gives the formulas, in both symbols and words, that are used to convert between the two scales.
table 1
situation temperature
fahrenheit celsius
water freezes 32°f 0°c
room temperature 68°f 20°c
normal body temperature 98.6°f 37°c
water boils 212°f 100°c
table 2
to convert from formula in symbols formula in words
fahrenheit to celsius c = \frac{5}{9}(f - 32) subtract 32, multiply by 5, then divide by 9
celsius to fahrenheit f = \frac{9}{5}c + 32 multiply by \frac{9}{5}, then add 32
let f = 32 in the formula c = \frac{5}{9}(f - 32), and solve for c.
does the value of c agree with the information in table 1?
question help: ebook post to forum
Step1: Substitute F value
Substitute $F = 32$ into $C=\frac{5}{9}(F - 32)$.
$C=\frac{5}{9}(32 - 32)$
Step2: Calculate the result
Since $32-32 = 0$, then $C=\frac{5}{9}\times0=0$.
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$0$
The value of $C$ agrees with the information in Table 1 as when water freezes, $F = 32^{\circ}F$ and $C = 0^{\circ}C$ in Table 1.