Question

question 24 of 25 what is the voltage drop across the 20 ω resistor? 10.0 ω 120.0 v 20.0 ω 30.0 ω a. 20 v b. 40 v c. 2 v d. 10 v

Explanation:

Step1: Calculate total resistance

The resistors are in series, so $R_{total}=10.0\Omega + 20.0\Omega+30.0\Omega = 60.0\Omega$.

Step2: Calculate total current

Using Ohm's law $I = \frac{V}{R}$, where $V = 120.0V$ and $R = R_{total}=60.0\Omega$. So $I=\frac{120.0V}{60.0\Omega}=2A$.

Step3: Calculate voltage drop across 20 - ohm resistor

Using Ohm's law again, $V = IR$. Here $I = 2A$ and $R = 20.0\Omega$, so $V=2A\times20.0\Omega = 40V$.

Answer:

B. 40 V