Question

question 1 of 25
which of the following are solutions to the quadratic equation? check all that apply.
$x^2 + 2x - 8 = 0$

a. 28
b. 4
c. 1
d. -4
e. -1
f. 2

Explanation:

Step1: Factor the quadratic equation

We factor \(x^2 + 2x - 8 = 0\) by finding two numbers that multiply to \(-8\) and add to \(2\). The numbers are \(4\) and \(-2\), so we can write the equation as \((x + 4)(x - 2)=0\).

Step2: Solve for \(x\)

Using the zero - product property, if \((x + 4)(x - 2)=0\), then either \(x+4 = 0\) or \(x - 2=0\).

• For \(x + 4=0\), we get \(x=-4\).
• For \(x - 2=0\), we get \(x = 2\).

Answer:

D. -4, F. 2