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question
\\(\overline{wx}\\) is dilated by a scale factor of \\(\frac{1}{4}\\) to form \\(\overline{wx}\\). \\(\overline{wx}\\) measures 9. what is the measure of \\(\overline{wx}\\)?
answer
attempt 1 out of 2
Step1: Recall dilation formula
Let the length of $\overline{WX}$ be $x$. The formula for dilation is $new\ length = scale\ factor\times original\ length$. Here, the new - length is the length of $\overline{W'X'}=9$, and the scale factor is $\frac{1}{4}$. So, $9=\frac{1}{4}x$.
Step2: Solve for $x$
To solve for $x$, we multiply both sides of the equation $9 = \frac{1}{4}x$ by $4$. So, $x=9\times4$.
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