Question

question 4.
divide:
$\frac{12x^5 - 4x^3}{3x}$
a. $9x^4 - \frac{4}{3}x$
b. $4x^4 - 4x^2$
c. $9x^4 - 4x^2$
d. $4x^4 - \frac{4}{3}x$

Explanation:

Step1: Split the fraction

$\frac{12x^5 - 4x^3}{3x} = \frac{12x^5}{3x} - \frac{4x^3}{3x}$

Step2: Simplify first term

$\frac{12x^5}{3x} = 4x^{5-1} = 4x^4$

Step3: Simplify second term

$\frac{4x^3}{3x} = \frac{4}{3}x^{3-1} = \frac{4}{3}x^2$

Step4: Combine simplified terms

$4x^4 - \frac{4}{3}x^2$

Answer:

D. $4x^4 - \frac{4}{3}x$