Question

question 2 of 9
draw the figure shown in the front, top, and side views.
front
side
top

Explanation:

Step1: Analyze Front View

The front view has a base row of 5 squares, with 2 additional squares stacked vertically on the 3rd square (from left) of the base row. So, the front - facing structure has a 5 - square base, and column 3 (1 - based index) has 3 squares (base + 2 stacked).

Step2: Analyze Top View

The top view is a single row of 5 squares. This means that when looking from the top, there is only one layer in the horizontal (x - y) plane, and the length along the row is 5 units (squares).

Step3: Analyze Side View

The side view is a column of 3 squares. This implies that along the depth (perpendicular to the front - back) direction, there is only one column of squares, and the height of this column is 3 squares.

Step4: Construct the 3D Figure

• Base Layer: From the top view, we know the base layer (z = 0, assuming z - axis is vertical) has 5 squares in a row (let's say along the x - axis, from x = 1 to x = 5, y = 1, z = 0).
• Vertical Stacking: From the front view, at x = 3, y = 1, we have additional squares at z = 1 and z = 2 (since the front view shows 3 squares in column 3). From the side view, since the side view (looking along the x - axis) shows 3 squares, this confirms that the column at x = 3, y = 1 has height 3 (z = 0,1,2). And since the top view has only one row (y = 1 for all x in 1 - 5), there are no other columns in the y - direction.

So the 3D figure is made up of a row of 5 cubes (in the base layer, z = 0, x = 1 - 5, y = 1) and on top of the middle (3rd) cube of this row, we stack 2 more cubes, making a total of 5+2 = 7 cubes, with the middle cube having a height of 3 and the other 4 cubes in the base row having a height of 1.

To draw it:

• Front View (already given): A row of 5 squares, with the 3rd square from the left having 2 more squares stacked on top.
• Top View (already given): A row of 5 squares.
• Side View (already given): A column of 3 squares.
• 3D Representation: Draw a horizontal line of 5 squares (base). Then, above the 3rd square (counting from the left) in this base line, draw 2 more squares stacked vertically, so that the 3rd square has a total of 3 squares (base + 2 stacked) and the other 4 squares have 1 square each. The depth (into the page) is 1 square (since the top view has only one row), so it's a sort of "T - shaped" structure in 3D but with the vertical part only on the middle of the horizontal base.

Answer:

The 3D figure consists of a horizontal row of 5 cubes (in the bottom layer) with the middle (3rd) cube having 2 additional cubes stacked vertically on top of it, resulting in a structure where the middle column has a height of 3 cubes and the other columns in the bottom row have a height of 1 cube. The figure can be drawn by first drawing the 5 - cube base row, then adding 2 cubes on top of the 3rd cube in this row.