QUESTION IMAGE
Question
question 9
evaluate the limit: $lim_{x \to 4}\frac{x^{2}+2x - 4}{x + 1}$.
dne
0
4
5
$infty$
Step1: Substitute x = 4
Substitute \(x = 4\) into the function \(\frac{x^{2}+2x - 4}{x + 1}\).
\[
$$\begin{align*}
\frac{4^{2}+2\times4-4}{4 + 1}&=\frac{16+8 - 4}{5}\\
&=\frac{20}{5}
\end{align*}$$
\]
Step2: Simplify the result
Simplify \(\frac{20}{5}\).
\(\frac{20}{5}=4\)
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