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Question
question
express as a trinomial.
$(x + 8)(2x - 10)$
Step1: Apply the distributive property (FOIL method)
Multiply the First terms: \(x \times 2x = 2x^2\)
Multiply the Outer terms: \(x \times (-10) = -10x\)
Multiply the Inner terms: \(8 \times 2x = 16x\)
Multiply the Last terms: \(8 \times (-10) = -80\)
So, \((x + 8)(2x - 10)=2x^2-10x + 16x-80\)
Step2: Combine like terms
Combine the \(x\)-terms: \(-10x + 16x = 6x\)
So the expression becomes \(2x^2+6x - 80\)
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\(2x^2 + 6x - 80\)