Question

question
factor completely.
49x^{2}y^{6}-25

Explanation:

Step1: Recognize difference - of - squares

The expression $49x^{2}y^{6}-25$ is in the form $a^{2}-b^{2}$, where $a = 7xy^{3}$ and $b = 5$.
Since $49x^{2}y^{6}=(7xy^{3})^{2}$ and $25 = 5^{2}$.

Step2: Apply difference - of - squares formula

The difference - of - squares formula is $a^{2}-b^{2}=(a + b)(a - b)$.
Substituting $a = 7xy^{3}$ and $b = 5$ into the formula, we get $(7xy^{3}+5)(7xy^{3}-5)$.

Answer:

$(7xy^{3}+5)(7xy^{3}-5)$