Question

question
find the distance between the two points rounding to the nearest tenth (if necessary).
(2, -3) and (8, -7)

Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $x_1 = 2$, $y_1=-3$, $x_2 = 8$, $y_2=-7$.

Step2: Calculate differences

First, find $x_2 - x_1$ and $y_2 - y_1$. $x_2 - x_1=8 - 2=6$, $y_2 - y_1=-7-( - 3)=-7 + 3=-4$.

Step3: Square the differences

Square the results from step 2. $(x_2 - x_1)^2=6^2 = 36$, $(y_2 - y_1)^2=(-4)^2 = 16$.

Step4: Sum the squared - differences

Add the squared differences: $(x_2 - x_1)^2+(y_2 - y_1)^2=36 + 16=52$.

Step5: Calculate the distance

Take the square - root of the sum: $d=\sqrt{52}\approx7.2$.

Answer:

$7.2$