Question

question
find the slope of the tangent line to the graph of (f(x)=3x^{2}-3x + 4) at (x = 1).
provide your answer below.

Explanation:

Step1: Find the derivative

The derivative of $f(x)=3x^{2}-3x + 4$ using the power - rule $\frac{d}{dx}(x^{n})=nx^{n - 1}$ is $f^\prime(x)=6x-3$.

Step2: Evaluate the derivative at $x = 1$

Substitute $x = 1$ into $f^\prime(x)$. So $f^\prime(1)=6\times1-3$.
$f^\prime(1)=6 - 3=3$.

Answer:

$3$