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question given $h(x) = -2x + 4$, solve for $x$ when $h(x) = -8$.

Question

question given $h(x) = -2x + 4$, solve for $x$ when $h(x) = -8$.

Explanation:

Step1: Substitute h(x) with -8

We know that \( h(x) = -2x + 4 \) and \( h(x) = -8 \), so we substitute \( h(x) \) in the first equation with -8, getting the equation \( -8 = -2x + 4 \).

Step2: Subtract 4 from both sides

To isolate the term with \( x \), we subtract 4 from both sides of the equation. So, \( -8 - 4 = -2x + 4 - 4 \), which simplifies to \( -12 = -2x \).

Step3: Divide both sides by -2

To solve for \( x \), we divide both sides of the equation \( -12 = -2x \) by -2. So, \( \frac{-12}{-2} = \frac{-2x}{-2} \), which gives \( x = 6 \).

Answer:

\( x = 6 \)