Question

question 6, 5.4.9
hw score: 29.41%, 5 of 17 points
points: 0 of 1
points e, d, and h are the midpoints of the sides of $delta tuv$. $uv = 118$, $tv = 142$, and $hd = 118$. find $he$.
$he = \square$

Explanation:

Step1: Apply Midsegment Theorem

In a triangle, the segment connecting midpoints of two sides is parallel to the third side and half its length. For $\Delta TUV$, $H$ and $E$ are midpoints, so $HE = \frac{1}{2}UV$.

Step2: Substitute given UV value

Given $UV = 118$, substitute into the formula.
$HE = \frac{1}{2} \times 118$

Answer:

$59$