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question let $k(x)=f(x)g(x)h(x)$. if $f(-3)=-6,f(-3)=-9,g(-3)=-1,g(-3)=…

Question

question let $k(x)=f(x)g(x)h(x)$. if $f(-3)=-6,f(-3)=-9,g(-3)=-1,g(-3)=9,h(-3)=6,$ and $h(-3)=-2,$ what is $k(-3)$? do not include \$k(-3)=$\ in your answer. for example, if your answer is $k(-3)=3$, you would enter 3. provide your answer below:

Explanation:

Step1: Apply product - rule

$k'(x)=f'(x)g(x)h(x)+f(x)g'(x)h(x)+f(x)g(x)h'(x)$

Step2: Substitute $x = - 3$

$k'(-3)=(-9)\times(-1)\times6+(-6)\times9\times6+(-6)\times(-1)\times(-2)$
$k'(-3)=54 - 324-12$
$k'(-3)=54-(324 + 12)=54 - 336=-282$

Answer:

-282