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Question
question 4 (multiple choice worth 1 points)(05.01r mc)solve $\frac{1}{25} = 5^{x + 4} LXB0 x = -6 LXB1 x = 2$
Step1: Rewrite left side as power of 5
$\frac{1}{25} = 5^{-2}$
Step2: Set exponents equal (same base)
$-2 = x + 4$
Step3: Solve for x
$x = -2 - 4$
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x = -6