Question

question 4 (multiple choice worth 2 points) (05.02r mc) solve $e^{2x} = 50$. round to the thousandths place. $x = 0.849$ $x = 1.699$ $x = 1.956$ $x = 3.912$

Explanation:

Step1: Take natural log of both sides

$\ln(e^{2x}) = \ln(50)$

Step2: Simplify left side using log rule

$2x = \ln(50)$

Step3: Calculate $\ln(50)$ value

$\ln(50) \approx 3.91202$

Step4: Solve for x

$x = \frac{3.91202}{2} \approx 1.956$

Answer:

x = 1.956