Question

question 1 (multiple choice worth 2 points) (distance on the coordinate plane lc) what is the distance between the points located at (7, -15) and (7, 22)? -37 units -7 units 7 units 37 units

Explanation:

Step1: Identify the coordinates

The two points are \((7, -15)\) and \((7, 22)\). Since the \(x\)-coordinates are the same (\(x = 7\)), the distance between them is the absolute difference of the \(y\)-coordinates.

Step2: Calculate the difference in y - coordinates

The formula for the distance between two points \((x_1,y_1)\) and \((x_2,y_2)\) when \(x_1=x_2\) is \(d=\vert y_2 - y_1\vert\). Here, \(y_1=- 15\) and \(y_2 = 22\). So \(y_2-y_1=22-(-15)=22 + 15=37\). Then \(\vert22-(-15)\vert=\vert37\vert = 37\). Also, distance cannot be negative, so we discard the negative options.

Answer:

37 units (the option corresponding to 37 units, e.g., if the options are labeled as A. - 37 units, B. - 7 units, C. 7 units, D. 37 units, then the answer is D. 37 units)