Question

question 2 (3 points)
the complement of one angle is 10 more than 4 times the angle. find both angles.
solve for x: x =
angle =
complement =

Explanation:

Step1: Set up the equation

Let the angle be $x$. The complement of the angle is $90 - x$. The equation is $90 - x=4x + 10$.

Step2: Solve for x

Add $x$ to both sides: $90=4x + 10+x$, which simplifies to $90 = 5x+10$. Then subtract 10 from both sides: $90 - 10=5x$, so $80 = 5x$. Divide both sides by 5: $x=\frac{80}{5}=16$.

Step3: Find the complement

The complement of the angle $x$ is $90 - x$. Substitute $x = 16$ into it, we get $90-16 = 74$.

Answer:

Solve for $x$: $x = 16$
Angle = $16$
Complement = $74$