Question

question 2
1 pts
a car is traveling at 25 m/s and the driver sees the light ahead change to read and presses the brakes. the car slows to a stop in 5 seconds.
a) what was the rate of acceleration of the vehicle as it slowed down?
b) how far does the car travel while slowing to a stop?

Explanation:

Step1: Calculate acceleration

Use the formula $a=\frac{v - u}{t}$, where $u = 25$ m/s (initial velocity), $v=0$ m/s (final velocity), and $t = 5$ s (time).
$a=\frac{0 - 25}{5}=- 5$ m/s²

Step2: Calculate distance

Use the formula $s=ut+\frac{1}{2}at^{2}$. Substitute $u = 25$ m/s, $a=-5$ m/s², and $t = 5$ s.
\[

$$\begin{align*} s&=25\times5+\frac{1}{2}\times(- 5)\times5^{2}\\ &=125-\frac{1}{2}\times5\times25\\ &=125 - 62.5\\ &=62.5\text{ m} \end{align*}$$

\]

Answer:

a) -5 m/s²
b) 62.5 m