Question

question
rewrite the volume formula to create an equation that can use used to calculate the radius, r, of the tank.
drag the terms to the correct locations in the equation. not all terms will be used.
image: equation structure ( r = sqrt{\frac{square}{square}} ) and terms: ( 400pi a ), ( 20a ), ( a ), ( 20pi ), ( 20v ), ( v )

Explanation:

Assuming the tank is a cylinder, the volume formula of a cylinder is \( V=\pi r^{2}h \) (here we assume the height - related term is \( 20\pi \) or other forms, but from the given terms, we can infer the process of solving for \( r \)).

Step 1: Start with the volume formula

Suppose the volume formula of the tank (cylinder - like) is \( V = 20\pi r^{2}\) (we assume the height - related part is \( 20\pi \) from the given terms). To solve for \( r \), we first divide both sides of the equation by \( 20\pi \):
\( \frac{V}{20\pi}=r^{2} \)

Step 2: Take the square root of both sides

To get \( r \), we take the square root of both sides of the equation \( r^{2}=\frac{V}{20\pi} \), so \( r = \sqrt{\frac{V}{20\pi}} \) (but from the given terms, if we adjust, maybe the formula is derived from a different form. Wait, the given terms have \( V \) and \( 20\pi \) and others. Wait, maybe the original volume formula is \( V=20\pi r^{2}\), then solving for \( r \):

First, divide both sides by \( 20\pi \): \( \frac{V}{20\pi}=r^{2} \)

Then take square root: \( r=\sqrt{\frac{V}{20\pi}} \)

But looking at the terms, we need to drag \( V \) to the numerator and \( 20\pi \) to the denominator inside the square root.

Answer:

\( r=\sqrt{\frac{V}{20\pi}} \) (So we drag \( V \) to the top box and \( 20\pi \) to the bottom box inside the square root, with \( r = \sqrt{\frac{\boldsymbol{V}}{\boldsymbol{20\pi}}} \))