Question

question
simplify: \\(\frac{-9p^3 + 21p^2}{3}\\)
answer attempt 3 out of 3

Explanation:

Step1: Split the fraction

We can split the fraction \(\frac{-9p^{3}+21p^{2}}{3}\) into two separate fractions: \(\frac{-9p^{3}}{3}+\frac{21p^{2}}{3}\)

Step2: Simplify each fraction

For the first fraction \(\frac{-9p^{3}}{3}\), divide \(-9\) by \(3\) to get \(-3\), so it simplifies to \(-3p^{3}\). For the second fraction \(\frac{21p^{2}}{3}\), divide \(21\) by \(3\) to get \(7\), so it simplifies to \(7p^{2}\). Combining these two simplified fractions, we get \(-3p^{3}+7p^{2}\). We can also factor out the common term \(p^{2}\) to get \(p^{2}(-3p + 7)\) or leave it as \(-3p^{3}+7p^{2}\).

Answer:

\(-3p^{3}+7p^{2}\) (or \(p^{2}(-3p + 7)\))