Question

question #2
simplify the rational expression $\frac{6x^{3}+12x^{2}-3x}{9x}$
$\frac{5x}{3}$
$\frac{2x^{2}+4x}{3}$
$\frac{2x^{2}+4x - 1}{3}$
$\frac{2x^{2}+3x}{3}$

Explanation:

Step1: Factor out the common factor in the numerator

$6x^{3}+12x^{2}-3x = 3x(2x^{2}+4x - 1)$

Step2: Simplify the rational - expression

$\frac{3x(2x^{2}+4x - 1)}{9x}=\frac{2x^{2}+4x - 1}{3}$ (Cancel out the common factor $3x$ in the numerator and the denominator, assuming $x
eq0$)

Answer:

$\frac{2x^{2}+4x - 1}{3}$