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question solve for x: 6(4x + 5) = 3x - 4(-4x - 1) + 5 answer attempt 1 …

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solve for x:
6(4x + 5) = 3x - 4(-4x - 1) + 5
answer
attempt 1 out of 2
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Explanation:

Step1: Expand both sides

$6(4x+5) = 24x + 30$
$3x - 4(-4x-1)+5 = 3x +16x +4 +5 = 19x +9$
Equation becomes: $24x + 30 = 19x + 9$

Step2: Isolate x terms

Subtract $19x$ from both sides:
$24x -19x +30 = 19x -19x +9$
$5x + 30 = 9$

Step3: Isolate constant terms

Subtract 30 from both sides:
$5x +30 -30 = 9 -30$
$5x = -21$

Step4: Solve for x

Divide both sides by 5:
$x = \frac{-21}{5}$

Answer:

$x = -\frac{21}{5}$