Question

question solve for m. answer attempt 1 out of 3

Explanation:

Step1: Use cosine - function definition

In a right - triangle, if the hypotenuse is $c$, the adjacent side to an angle $\theta$ is $a$, then $\cos\theta=\frac{a}{c}$. Here, the hypotenuse $c = m$, the adjacent side to the $60^{\circ}$ angle is $\sqrt{10}$, and $\theta = 60^{\circ}$. We know that $\cos60^{\circ}=\frac{1}{2}$. According to the cosine formula $\cos60^{\circ}=\frac{\sqrt{10}}{m}$.

Step2: Solve for $m$

Since $\cos60^{\circ}=\frac{\sqrt{10}}{m}$ and $\cos60^{\circ}=\frac{1}{2}$, we can cross - multiply to get $m\times1 = 2\times\sqrt{10}$.

Answer:

$m = 2\sqrt{10}$