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Question
question
solve for x:
\sqrt{6x + 48} - 1 = 5
answer attempt 1 out of 2
x =
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Step1: Isolate the square root term
Add 1 to both sides of the equation $\sqrt{6x + 48}-1 = 5$ to get $\sqrt{6x + 48}=5 + 1$.
Simplifying the right side gives $\sqrt{6x + 48}=6$.
Step2: Eliminate the square root
Square both sides of the equation $\sqrt{6x + 48}=6$ to obtain $6x + 48 = 6^2$.
Calculating $6^2$ gives $6x + 48 = 36$.
Step3: Solve for x
Subtract 48 from both sides: $6x=36 - 48$.
Simplifying the right side: $6x=- 12$.
Divide both sides by 6: $x=\frac{-12}{6}$.
Simplifying gives $x = - 2$.
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$x=-2$