Question

question
solve the following inequality algebraically.
|x + 3| ≤ 8

Explanation:

Step1: Rewrite absolute value inequality

$-8 \leq x + 3 \leq 8$

Step2: Subtract 3 from all parts

$-8 - 3 \leq x \leq 8 - 3$

Step3: Simplify all terms

$-11 \leq x \leq 5$

Answer:

$-11 \leq x \leq 5$