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question solve for x. round to the nearest tenth of a degree, if necess…

Question

question solve for x. round to the nearest tenth of a degree, if necessary.

Explanation:

Step1: Identify the trigonometric ratio

In right - triangle $\triangle WUV$, we know the opposite side ($w = 7.9$) and the hypotenuse ($h=15$) with respect to angle $x$. We use the sine ratio $\sin x=\frac{\text{opposite}}{\text{hypotenuse}}$. So, $\sin x=\frac{7.9}{15}$.

Step2: Solve for $x$

We have $\sin x=\frac{7.9}{15}\approx0.5267$. Then, $x = \sin^{- 1}(0.5267)$.

Step3: Calculate the value of $x$

Using a calculator, $x=\sin^{-1}(0.5267)\approx31.8^{\circ}$.

Answer:

$31.8^{\circ}$