Question

question 2. what is the equation of the line in point slope form? x | y -6 | 14 -12 | 12 -18 | 10 \bigcirc y - 14 = -\frac{1}{3}(x - 6) \bigcirc y - 14 = \frac{1}{3}(x + 6) \bigcirc y = -\frac{1}{3}x + 16 \bigcirc y = \frac{1}{3}x + 16

Explanation:

Step1: Calculate slope $m$

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{12-14}{-12-(-6)}=\frac{-2}{-6}=-\frac{1}{3}$

Step2: Recall point-slope formula

The formula is $y-y_1=m(x-x_1)$

Step3: Substitute point $(-6,14)$

$y-14 = -\frac{1}{3}(x-(-6))$

Step4: Simplify the equation

$y-14 = -\frac{1}{3}(x+6)$

Answer:

$y-14 = -\frac{1}{3}(x+6)$