Question

question
what is the value of $\log_{2} \frac{1}{16}$?
answer attempt 1 out of 12

Explanation:

Step1: Recall the logarithm property $log_a\frac{1}{x}=-log_a x$

$log_2\frac{1}{16}=-log_2 16$

Step2: Express 16 as a power of 2, $16 = 2^4$

$-log_2 2^4$

Step3: Use the logarithm property $log_a a^b = b$

$-4$

Answer:

-4