Question

question 4
which list of numbers is in order from least to greatest?
$2, \sqrt{5}, \sqrt{32}, 3$
$\sqrt{32}, 3, \sqrt{5}, 2$
$2, \sqrt{5}, 3, \sqrt{32}$
$2, 3, \sqrt{5}, \sqrt{32}$

Explanation:

Step1: Calculate approximate values

First, find the approximate values of the square roots.

• $\sqrt{5} \approx 2.24$ (since $2^2 = 4$ and $3^2 = 9$, so $\sqrt{5}$ is between 2 and 3, closer to 2)
• $\sqrt{32} = \sqrt{16\times2} = 4\sqrt{2} \approx 4\times1.414 = 5.656$
• The other numbers are 2 and 3.

Step2: Compare the values

Now compare the numbers: 2, $\sqrt{5} \approx 2.24$, 3, $\sqrt{32} \approx 5.656$.
So ordering from least to greatest: 2, $\sqrt{5}$, 3, $\sqrt{32}$.

Answer:

$2, \sqrt{5}, 3, \sqrt{32}$ (the third option: $2, \sqrt{5}, 3, \sqrt{32}$)