QUESTION IMAGE
Question
read 6.1 angles of a triangle (textbook pgs. 335-338)
exterior angle theorem: the measure of an exterior angle of a triangle is equal to the sum of the measures of the two remote interior angles. ( mangle 1 = mangle a + mangle b )
example 1: find ( mangle 1 ).
triangle ( rst ) with ( angle r = 80^circ ), ( angle s = 60^circ ), exterior angle ( angle 1 ) at ( t ).
( mangle 1 = mangle r + mangle s ) (exterior angle theorem)
( = 80 + 60 ) (substitution)
( = 140 ) (simplify)
example 2: find ( x ).
triangle ( sqr ) with ( angle r = 55^circ ), exterior angle ( angle pqs = 78^circ ), ( angle s = x ).
( mangle pqs = mangle r + mangle s ) (exterior angle theorem)
( 78 = 55 + x ) (substitution)
( 23 = x ) (subtract 55 from each side)
exercises
find the measures of each numbered angle.
- triangle ( xyz ) with ( angle x = 50^circ ), ( angle y = 65^circ ), exterior angle ( angle 1 ) at ( z ).
- triangle ( abc ) with ( angle b = 25^circ ), ( angle a = 35^circ ), angles ( angle 1 ), ( angle 2 ) at ( c ).
find each measure.
- ( mangle abc ): triangle ( abc ) with ( angle a = 95^circ ), exterior angle at ( c ) is ( 145^circ ), ( angle b = 2x^circ ).
- ( mangle f ): triangle ( efg ) with exterior angle at ( g ) is ( 58^circ ), ( angle e = x ), ( angle f = x ).
Exercise 1: Find \( m\angle 1 \)
Step 1: Apply Exterior Angle Theorem
The Exterior Angle Theorem states that the measure of an exterior angle of a triangle is equal to the sum of the measures of the two remote interior angles. For \( \triangle XYZ \), \( m\angle 1 = m\angle X + m\angle Y \).
\( m\angle 1 = 50^\circ + 65^\circ \)
Step 2: Simplify
Add the two angles: \( 50 + 65 = 115 \)
\( m\angle 1 = 115^\circ \)
Step 1: Apply Exterior Angle Theorem
For \( \triangle ABC \), \( m\angle 1 = m\angle A + m\angle B \).
\( m\angle 1 = 35^\circ + 25^\circ \)
Step 2: Simplify
Add the two angles: \( 35 + 25 = 60 \)
\( m\angle 1 = 60^\circ \)
For \( m\angle 2 \):
Step 1: Linear Pair
\( \angle 1 \) and \( \angle 2 \) form a linear pair, so \( m\angle 1 + m\angle 2 = 180^\circ \).
\( 60^\circ + m\angle 2 = 180^\circ \)
Step 2: Solve for \( m\angle 2 \)
Subtract \( 60^\circ \) from both sides: \( m\angle 2 = 180^\circ - 60^\circ = 120^\circ \)
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\( m\angle 1 = 115^\circ \)