Question

1. rectangle cdef with vertices c(-1,6), d(0,8), e(6,5), and f(5,3): 270° clockwise

rule: (x,y)→
image
c ( )
d ( )
e ( )
f ( )

Explanation:

Step1: Recall rotation rule

The rule for a 270 - degree clockwise rotation about the origin is $(x,y)\to(y, - x)$.

Step2: Apply rule to point C(-1,6)

For point C(-1,6), substituting $x=-1$ and $y = 6$ into the rule $(x,y)\to(y,-x)$, we get $C'=(6,1)$.

Step3: Apply rule to point D(0,8)

For point D(0,8), substituting $x = 0$ and $y=8$ into the rule $(x,y)\to(y,-x)$, we get $D'=(8,0)$.

Step4: Apply rule to point E(6,5)

For point E(6,5), substituting $x = 6$ and $y = 5$ into the rule $(x,y)\to(y,-x)$, we get $E'=(5,-6)$.

Step5: Apply rule to point F(5,3)

For point F(5,3), substituting $x = 5$ and $y = 3$ into the rule $(x,y)\to(y,-x)$, we get $F'=(3,-5)$.

Answer:

Rule: $(x,y)\to(y,-x)$
$C'(6,1)$
$D'(8,0)$
$E'(5,-6)$
$F'(3,-5)$