Question

retake velocity assessment
person a is walking at a velocity of 2 m/s south. person b is walking at a velocity of 5 m/s north. if the two people started at the same spot, what is the distance between them after 20 seconds?
40 m
60 m
140 m
240 m

Explanation:

Step1: Calculate distance of person A

Use formula $d = vt$, where $v = 2$ m/s and $t = 20$ s. So $d_A=2\times20 = 40$ m.

Step2: Calculate distance of person B

Use formula $d = vt$, where $v = 5$ m/s and $t = 20$ s. So $d_B=5\times20 = 100$ m.

Step3: Calculate distance between them

Since they are moving in opposite - directions, $d=d_A + d_B$. So $d=40 + 100=140$ m.

Answer:

140 m