Question

rewrite the following without an exponent. 8^{-2}

Explanation:

Step1: Apply negative - exponent rule

According to the rule \(a^{-n}=\frac{1}{a^{n}}\), for \(a = 8\) and \(n = 2\), we have \(8^{-2}=\frac{1}{8^{2}}\).

Step2: Calculate \(8^{2}\)

\(8^{2}=8\times8 = 64\). So \(\frac{1}{8^{2}}=\frac{1}{64}\).

Answer:

\(\frac{1}{64}\)