Question

rewrite the following without an exponent.
$9^{-2}$

Explanation:

Step1: Recall the negative exponent rule

The rule for a negative exponent is \( a^{-n}=\frac{1}{a^{n}} \), where \( a
eq0 \) and \( n \) is a positive integer. So for \( 9^{-2} \), we can apply this rule to get \( \frac{1}{9^{2}} \).

Step2: Calculate \( 9^{2} \)

We know that \( 9^{2}=9\times9 = 81 \). So substituting back, we have \( \frac{1}{81} \).

Answer:

\(\frac{1}{81}\)