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Question
rewrite using a radical/root symbol:
- ( x^{1/2} )
- ( y^{\frac{5}{7}} )
- ( 6^{\frac{10}{15}} )
- ( 17490^{\frac{23}{78}} )
Step1: Apply rational exponent rule
Recall the rule: $a^{\frac{m}{n}} = \sqrt[n]{a^m}$
Step2: Rewrite each term with radicals
- For $x^{\frac{1}{2}}$: $m=1$, $n=2$, so $\sqrt[2]{x^1} = \sqrt{x}$
- For $y^{\frac{5}{7}}$: $m=5$, $n=7$, so $\sqrt[7]{y^5}$
- For $6^{\frac{10}{15}}$: Simplify exponent first: $\frac{10}{15}=\frac{2}{3}$, then $\sqrt[3]{6^2}$
- For $17490^{\frac{23}{78}}$: $m=23$, $n=78$, so $\sqrt[78]{17490^{23}}$
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- $\sqrt{x}$
- $\sqrt[7]{y^5}$
- $\sqrt[3]{6^2}$ (or simplified form $\sqrt[3]{36}$)
- $\sqrt[78]{17490^{23}}$