Question

the routes of two planes are shown. they take off from the same airport at the same time. 3. plane 1 travels 1,600 nautical miles to its destination in 4 hours. plane 2 travels 2,000 nautical miles to its destination in 5 hours. which planes average speed is faster? a. plane 1 b. plane 2 c. plane 1 and 2 have the same average speed

Explanation:

Step1: Recall speed formula

Speed $v=\frac{d}{t}$, where $d$ is distance and $t$ is time.

Step2: Calculate speed of Plane 1

For Plane 1, $d_1 = 1600$ nautical - miles and $t_1=4$ hours. So $v_1=\frac{d_1}{t_1}=\frac{1600}{4}=400$ nautical - miles per hour.

Step3: Calculate speed of Plane 2

For Plane 2, $d_2 = 2000$ nautical - miles and $t_2 = 5$ hours. So $v_2=\frac{d_2}{t_2}=\frac{2000}{5}=400$ nautical - miles per hour.

Answer:

C. Plane 1 and 2 have the same average speed