Question

russell has 8 bills in his wallet, all $5 bills and $20 bills. if he has $85.00 in his wallet, how many $5 bills does he have?
○ two $5 bills
○ three $5 bills
○ six $5 bills
○ five $5 bills
clear my selection

Explanation:

Step1: Define variables

Let \( x \) be the number of \$5 bills and LXI1 be the number of \$20 bills. We know two equations: \( x + y = 8 \) (total number of bills) and \( 5x + 20y = 85 \) (total amount of money).

Step2: Solve the first equation for \( y \)

From \( x + y = 8 \), we get \( y = 8 - x \).

Step3: Substitute \( y \) into the second equation

Substitute \( y = 8 - x \) into \( 5x + 20y = 85 \):
\( 5x + 20(8 - x) = 85 \)
Expand: \( 5x + 160 - 20x = 85 \)
Simplify: \( -15x + 160 = 85 \)
Subtract 160: \( -15x = 85 - 160 = -75 \)
Divide by -15: \( x = \frac{-75}{-15} = 5 \)

Answer:

five \$5 bills