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score on last try: 6.67 of 10 pts. see details for more. at least one scored part is incorrect. jump to first changeable > next question get a similar question you can r the function graphed above is decreasing on the interval -3 < x < -1 the inflection point is at x = -2 question help: video
Step1: Determine decreasing - interval condition
A function $y = f(x)$ is decreasing when its derivative $f'(x)<0$. Visually, on a graph, the function is decreasing when the curve goes down - hill as we move from left to right.
Step2: Analyze the graph
Looking at the given graph, we can see that the function is going down - hill (decreasing) on the interval $- 3 An inflection point is a point where the concavity of the function changes, i.e., where the second - derivative $f''(x) = 0$ and changes sign. Visually, it is the point where the graph changes from being concave up to concave down or vice - versa. In the given graph, the inflection point occurs at $x=-2$ as the graph changes concavity at this point.Step3: Identify inflection - point condition
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The function is decreasing on the interval $-3 < x < 1$. The inflection point is at $x=-2$.