QUESTION IMAGE
Question
select the choice that best answers each question or completes each statement.
- which of these series of units is ordered from smallest to largest?
(a) μg, cg, mg, kg
(b) mm, dm, m, km
(c) μs, ns, cs, s
(d) nl, ml, dl, cl
- which answer represents the measurement 0.00428 g rounded to two significant figures?
(a) 4.28×10³ g
(b) 4.3×10³ g
(c) 4.3×10⁻³ g
(d) 4.0×10⁻³ g
- an over - the - counter medicine has 325 mg of its active ingredient per tablet. how many grams does this mass represent?
(a) 325,000 g
(b) 32.5 g
(c) 3.25 g
(d) 0.325 g
- if 10⁴ μm = 1 cm, how many μm³ = 1 cm³?
(a) 10⁴
(b) 10⁶
(c) 10⁸
(d) 10¹²
- if a substance contracts when it freezes, its
(a) density will remain the same.
(b) density will increase.
(c) density will decrease.
(d) change in density cannot be predicted.
Step1: Recall metric - prefix order
The metric prefixes in order of increasing magnitude: micro ($\mu$) = $10^{- 6}$, centi (c) = $10^{-2}$, milli (m) = $10^{-3}$, deci (d) = $10^{-1}$, kilo (k) = $10^{3}$. For time, nano (n) = $10^{-9}$, micro ($\mu$) = $10^{-6}$, centi (c) = $10^{-2}$, second (s). For volume, nano (n) = $10^{-9}$, milli (m) = $10^{-3}$, deci (d) = $10^{-1}$, centi (c) = $10^{-2}$.
For option A: $\mu g=10^{-6}g$, $cg = 10^{-2}g$, $mg=10^{-3}g$, $kg = 10^{3}g$. The correct order from smallest to largest is $\mu g,mg,cg,kg$.
For option B: $mm = 10^{-3}m$, $dm=10^{-1}m$, $m = 1m$, $km = 10^{3}m$. This is in the correct order from smallest to largest.
For option C: $ns=10^{-9}s$, $\mu s = 10^{-6}s$, $cs=10^{-2}s$, $s = 1s$. The correct order from smallest to largest is $ns,\mu s,cs,s$.
For option D: $nL=10^{-9}L$, $mL = 10^{-3}L$, $dL=10^{-1}L$, $cL=10^{-2}L$. The correct order from smallest to largest is $nL,mL,cL,dL$. So the answer to question 1 is B.
Step2: Rounding significant - figures
The number is $0.00428g$. The first non - zero digit is 4. To round to two significant figures, we look at the third digit. Since 8 > 5, we round up the second digit. $0.00428\approx4.3\times10^{-3}g$. So the answer to question 2 is C.
Step3: Unit conversion
We know that $1g = 1000mg$ or $1mg=\frac{1}{1000}g = 10^{-3}g$. Given $325mg$, then $325mg=325\times10^{-3}g = 0.325g$. So the answer to question 3 is D.
Step4: Volume unit conversion
If $10^{4}\mu m = 1cm$, then $(10^{4}\mu m)^{3}=(1cm)^{3}$. Using the power - of - a - power rule $(a^{m})^{n}=a^{mn}$, we have $(10^{4})^{3}\mu m^{3}=1cm^{3}$, and $(10^{4})^{3}=10^{12}$. So $10^{12}\mu m^{3}=1cm^{3}$. The answer to question 4 is D.
Step5: Density formula application
The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass, and $V$ is volume. When a substance contracts (volume $V$ decreases) upon freezing and the mass $m$ remains constant (mass is conserved), according to the formula $
ho=\frac{m}{V}$, as $V$ decreases and $m$ is constant, $
ho$ increases. So the answer to question 5 is B.
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- B. mm, dm, m, km
- C. $4.3\times10^{-3}g$
- D. $0.325g$
- D. $10^{12}$
- B. density will increase.