Question

select the correct answer from the drop-down menu.
$a = \

$$\begin{bmatrix}\\sqrt{2} & 1 \\\\ 1 & \\sqrt{2} \\\\ \\sqrt{2} & 1\\end{bmatrix}$$

$ $b = \

$$\begin{bmatrix}2 & 1 & 2 \\\\ 1 & 2 & 1\\end{bmatrix}$$

$ $c = \

$$\begin{bmatrix}2 & 1 \\\\ 1 & 2 \\\\ 2 & 1\\end{bmatrix}$$

$ $d = \

$$\begin{bmatrix}\\sqrt{4} & 1 \\\\ 1 & \\sqrt{4} \\\\ \\sqrt{4} & 1\\end{bmatrix}$$

$
the equivalent matrices are
a and b
c and d
d and a
b and c

Explanation:

Step1: Simplify $\sqrt{4}$

$\sqrt{4}=2$

Step2: Rewrite matrix D

$D =

$$\begin{bmatrix} 2 & 1 \\ 1 & 2 \\ 2 & 1 \end{bmatrix}$$

$

Step3: Compare matrices

Matrix $C =

$$\begin{bmatrix} 2 & 1 \\ 1 & 2 \\ 2 & 1 \end{bmatrix}$$

$, so $C=D$.

Answer:

C and D